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Given A To prove Construction Draw Proof Since A, E and D are collinear and BC || AD
Now,
From Eq (1) and Eq (2) | ![]() |
ILLUSTRATION P and Q are any two points lying on the side DC and AD respectively of a parallelogram ABCD. Show that ar(APB)= ar(BQC)
Solution: Now
Similarly
From Eq (1) and Eq (2) Hence Proved | ![]() |
X and Y are respectively two points on the sides DC and AD of the parallelogram
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| Right Option : D | |||
| View Explanation | |||
If KLMN is a parallelogram and a KOL is a triangle with area x
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| Right Option : A | |||
| View Explanation | |||
X and Y are respectively two points on the sides DC and AD of the parallelogram
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| Right Option : B | |||
| View Explanation | |||
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